Physics Circle home Student Login

Home›Chapters›Heat Transfer and Radiation PYQs›Heat Conduction›Question 23

MHT CET 2023 (13 May, Shift 1) · Heat Conduction

Heat Conduction question from MHT CET 2023 (13 May, Shift 1)

Q23MHT CET 2023 · 13 MAY · SHIFT 1Easy

Heat Conduction

The temperature gradient in a rod of length 75 cm75\text{ cm} is 40∘C/m40^\circ\text{C/m}. If the temperature of cooler end of the rod is 10∘C10^\circ\text{C}, then the temperature of hotter end is

Show answer and solution

Answer: (b)

  1. Temperature difference =gradient×length=40×0.75=30∘C= \text{gradient} \times \text{length} = 40 \times 0.75 = 30^\circ\text{C}
  2. Hot end =10+30=40∘C= 10 + 30 = 40^\circ\text{C}
  3. So the answer is (b) 40∘C40^\circ\text{C}.
Report a mistake

More questions on Heat Conduction