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MHT CET 2025 (22 Apr, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2025 (22 Apr, Shift 1)

Q13MHT CET 2025 · 22 APR · SHIFT 1Easy

Thermometry & Thermal Expansion

The temperature of a body on Kelvin scale is ' $x$ ' $K$ . When it is measured by a Fahrenheit thermometer, it is found to be ' x ' $^\circ\text{F}$ . The value of ' $x$ ' is (nearly)

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Answer: (c)

$K=C+273$ and $\frac{C}{5}=\frac{F-32}{9}$ , so $F=\frac{9}{5}(K-273)+32$ .
Put $F=K=x$ : $5x=9x-2457+160 \Rightarrow 4x=2297$
$x\approx 574$
So the answer is (c) 574.

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