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NEET 2005 (AIPMT) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from NEET 2005 (AIPMT)

Q73NEET 2005 · AIPMTEasy

Electrical Power & Heating Effect

The temperature of inversion of a thermocouple is 620∘C620^\circ\text{C} and the neutral temperature is 300∘C300^\circ\text{C}. What is the temperature of cold junction?

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Answer: (c)

  1. Tn=Tc+Ti2⇒Tc=2Tn−TiT_n = \dfrac{T_c + T_i}{2} \Rightarrow T_c = 2T_n - T_i.
  2. Tc=2(300)−620=−20∘CT_c = 2(300) - 620 = -20^\circ\text{C}.
  3. So the answer is (c) −20∘C-20^\circ\text{C}.
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