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JEE Main 2003 (AIEEE) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from JEE Main 2003 (AIEEE)

Q85JEE Main 2003 · AIEEEMedium

Electrical Power & Heating Effect

The thermo e.m.f.\text{e.m.f.} of a thermo -couple is 25 μV/∘C25\ \mu\text{V}/^\circ\text{C} at room temperature. A galvanometer of 40 ohm40\text{ ohm} resistance, capable of detecting current as low as 10−5 A,10^{-5}\text{ A}, is connected with the thermo couple. The smallest temperature difference that can be detected by this system is

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Answer: (a)

  1. Minimum emf needed =IR=10−5×40=4×10−4= IR = 10^{-5} \times 40 = 4 \times 10^{-4} V =400 μ= 400\ \muV.
  2. Δθ=400 μV25 μV/∘C=16∘\Delta\theta = \frac{400\ \mu\text{V}}{25\ \mu\text{V}/^\circ\text{C}} = 16^\circC
  3. So the answer is (a).
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