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JEE Main 2004 (AIEEE) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from JEE Main 2004 (AIEEE)

Q80JEE Main 2004 · AIEEEMedium

Electrical Power & Heating Effect

The thermo emf\text{emf} of a thermocouple varies with temperature θ\theta of the hot junction as E=aθ+bθ2E = a\theta + b\theta^2 in volts where the ratio a/ba/b is 700∘C.700^\circ\text{C}. If the cold junction is kept at 0∘C,0^\circ\text{C}, then the neutral temperature is

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Answer: (d)

  1. Neutral temperature: dEdθ=a+2bθ=0⇒θn=−a2b\frac{dE}{d\theta} = a + 2b\theta = 0 \Rightarrow \theta_n = -\frac{a}{2b}.
  2. θn=−7002=−350∘\theta_n = -\frac{700}{2} = -350^\circC, which is below the cold junction at 0∘0^\circC.
  3. A neutral temperature must lie above the cold-junction temperature, so none is possible: answer (d).
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