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MHT CET 2025 (20 Apr, Shift 2) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from MHT CET 2025 (20 Apr, Shift 2)

Q11MHT CET 2025 · 20 APR · SHIFT 2Easy

Satellites - Orbital Velocity & Period

The time period of a satellite of earth is 24 hours. If the separation between the earth and the satellite is decreased to one fourth of the previous value then its new time period will become

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Answer: (a)

Kepler's third law: $T \propto r^{3/2}$ .
$T' = 24 \times \left(\frac{1}{4}\right)^{3/2} = \frac{24}{8} = 3$ hours
So the answer is (a) 3 hours.

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