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MHT CET 2023 (11 May, Shift 1) · Simple Pendulum

Simple Pendulum question from MHT CET 2023 (11 May, Shift 1)

Q45MHT CET 2023 · 11 MAY · SHIFT 1Easy

Simple Pendulum

The time period of a simple pendulum inside a stationary lift is ' $T$ '. When the lift starts accelerating upwards with an acceleration $\left(\frac{g}{3}\right)$ , the time period of the pendulum will be

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Answer: (b)

Lift accelerating up: $g_{eff} = g + \frac{g}{3} = \frac{4g}{3}$ .
$T' = T\sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{2}T$
So the answer is (b).

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