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NEET 1999 (AIPMT) · Simple Pendulum

Simple Pendulum question from NEET 1999 (AIPMT)

Q86NEET 1999 · AIPMTEasy

Simple Pendulum

The time period of a simple pendulum is $2\text{ s}$ . If its length is increased by 4 times, then its period becomes

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Answer: (d)

$T \propto \sqrt{l}$
$l' = 4l \Rightarrow T' = 2T = 2 \times 2 = 4$ s
So the answer is (d) $4$ s.

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