Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Satellites - Orbital Velocity & Period›Question 73

JEE Main 2003 (AIEEE) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2003 (AIEEE)

Q73JEE Main 2003 · AIEEEEasy

Satellites - Orbital Velocity & Period

The time period of satellite of earth is 55 hours. If the separation between the earth and the satellite is increased to 44 times the previous value, the new time period will become

Show answer and solution

Answer: (c)

  1. Kepler's third law: T∝r3/2T \propto r^{3/2}.
  2. T′=5×43/2=5×8=40T' = 5 \times 4^{3/2} = 5 \times 8 = 40 hours
  3. So the answer is (c) 4040 hours.
Report a mistake

More questions on Satellites - Orbital Velocity & Period