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JEE Main 2026 (4 Apr, Shift 1) · Friction on an Incline

Friction on an Incline question from JEE Main 2026 (4 Apr, Shift 1)

Q3JEE Main 2026 · 4 APR · SHIFT 1Medium

Friction on an Incline

The time taken by a block of mass mm to slide down from the highest point to the lowest point on a rough inclined plane is 50%50\% more compared to the time taken by the same block on identical inclined smooth plane. Both inclined planes are at 45∘45^\circ with the horizontal. The coefficient of kinetic friction between the rough inclined surface and block is ______

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Answer: (c)

  1. At 45∘45^\circ: trts=a0a=11−μ\dfrac{t_r}{t_s} = \sqrt{\dfrac{a_0}{a}} = \dfrac{1}{\sqrt{1-\mu}}.
  2. 50% more time: trts=1.5⇒1−μ=12.25=49\dfrac{t_r}{t_s} = 1.5 \Rightarrow 1 - \mu = \dfrac{1}{2.25} = \dfrac{4}{9}
  3. So the answer is (c) μ=59\mu = \dfrac{5}{9}.
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