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MHT CET 2022 (11 Aug, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2022 (11 Aug, Shift 2)

Q42MHT CET 2022 · 11 AUG · SHIFT 2Medium

Periodic Motion & SHM Basics

The time taken by a particle executing simple harmonic motion of period 'TT', to move from the mean position to half the maximum displacement is

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Answer: (a)

  1. x=Asin⁡ωt=A2⇒ωt=π6x = A\sin\omega t = \frac{A}{2} \Rightarrow \omega t = \frac{\pi}{6}
  2. t=π/62π/T=T12t = \frac{\pi/6}{2\pi/T} = \frac{T}{12}
  3. So the answer is (a) T12\frac{T}{12}.
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