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JEE Main 2019 (9 Jan, Shift 2) · Velocity of Efflux (Torricelli)

Velocity of Efflux (Torricelli) question from JEE Main 2019 (9 Jan, Shift 2)

Q24JEE Main 2019 · 9 JAN · SHIFT 2Medium

Velocity of Efflux (Torricelli)

The top of a water tank is open to air and its water level is mainted. It is giving out 0.74 m3 water per minute through a circular opening of 2 cm radius in its wall. The depth of the center of the opening from the level of water in the tank is close to:

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Answer: (b)

  1. Q=0.7460=1.23×10−2 m3/sQ = \frac{0.74}{60} = 1.23\times10^{-2}\text{ m}^3\text{/s}, a=π(0.02)2=1.26×10−3 m2a = \pi(0.02)^2 = 1.26\times10^{-3}\text{ m}^2
  2. v=Qa≈9.8 m/sv = \frac{Q}{a} \approx 9.8\text{ m/s}
  3. h=v22g=962(10)≈4.8 mh = \frac{v^2}{2g} = \frac{96}{2(10)} \approx 4.8\text{ m}
  4. So the answer is (b) 4.8 m.
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