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JEE Main 2021 (22 Jul, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2021 (22 Jul, Shift 2)

Q86JEE Main 2021 · 22 JUL · SHIFT 2Medium

Electric Flux & Gauss's Law

The total charge enclosed in an incremental volume of 2 ×\times 10−-9 m3 located at the origin is ___________ nC, if electric flux density of its field is found as

D = e−-x sin y i^−\hat{i} - e−-x cos y j^\hat{j} + 2z k^\hat{k} C/m2

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. Gauss's law in point form: ρ=∇⋅D⃗\rho = \nabla\cdot\vec D.
  2. ∇⋅D⃗=−e−xsin⁡y+e−xsin⁡y+2=2\nabla\cdot\vec D = -e^{-x}\sin y + e^{-x}\sin y + 2 = 2 C/m3^3
  3. Q=ρV=2×2×10−9=4×10−9Q = \rho V = 2\times2\times10^{-9} = 4\times10^{-9} C =4= 4 nC.
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