Combination of Resistors question from JEE Main 2004 (AIEEE)

Answer: (a)

1. The top arc is a plain wire, so the top-left and top-right junctions are one node T; the battery is between T and the lower-left junction L.
2. $2\ \Omega$ and $6\ \Omega$ both join T to the centre: $2 \parallel 6 = 1.5\ \Omega$; with $1.5\ \Omega$ to L in series: $3\ \Omega$.
3. This $3\ \Omega$ is in parallel with the $3\ \Omega$ on the right arc (T to L): $R_{eq} = 1.5\ \Omega$.
4. $I = \dfrac{6}{1.5} = 4$ A. So the answer is (a) 4 A.