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MHT CET 2025 (21 Apr, Shift 1) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2025 (21 Apr, Shift 1)

Q4MHT CET 2025 · 21 APR · SHIFT 1Easy

Satellite Energy & Weightlessness

The total energy of a circularly orbiting satellite is

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Answer: (b)

  1. U=−GMmrU = -\frac{GMm}{r}, K=GMm2rK = \frac{GMm}{2r}, E=−GMm2rE = -\frac{GMm}{2r}.
  2. So E=U2E = \frac{U}{2} (and E=−KE = -K).
  3. So the answer is (b) half the potential energy.
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