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MHT CET 2026 (19 May, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2026 (19 May, Shift 2)

Q1MHT CET 2026 · 19 MAY · SHIFT 2Easy

Energy in SHM

The total energy of a particle executing SHM is $E$ . If the amplitude is doubled and the frequency is halved, the new total energy will be

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Answer: (b)

$E = \dfrac{1}{2}m\omega^2A^2 \propto f^2A^2$
$E' \propto \left(\dfrac{f}{2}\right)^2(2A)^2 = f^2A^2$
So $E' = E$ ; the answer is (b) $E$ .

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