Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Self-Inductance & Energy›Question 74

JEE Main 2019 (9 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from JEE Main 2019 (9 Apr, Shift 1)

Q74JEE Main 2019 · 9 APR · SHIFT 1Medium

Self-Inductance & Energy

The total number of turns and cross-section area in a solenoid is fixed. However, its length L is varied by adjusting the separation between windings. The inductance of solenoid will be proportional to:

Show answer and solution

Answer: (b)

  1. L=μ0N2ALlenL = \dfrac{\mu_0 N^2 A}{L_{\text{len}}} with total NN and AA fixed.
  2. So inductance ∝1L\propto \dfrac{1}{L}.
  3. So the answer is (b) 1/L1/L.
Report a mistake

More questions on Self-Inductance & Energy