The trajectory of projectile, projected from the ground is given by y = x - x²20. Where x and y are measured in meter. The maximum height attained by the projectile will be. (a) 10 m (b) 5 m (c) 200 m (d) 10 √(2) m

Answer: (b). y = 0 at x = 0 and x = 20, so range R = 20 m; maximum at x = 10 m H = 10 - 100/20 = 5 m So the answer is (b) 5 m.

The trajectory of projectile, projected from the ground is given by y… | JEE Main 2023 (8 Apr, Shift 2)

Q2JEE Main 2023 · 8 APR · SHIFT 2Medium

Projectile Basics & Trajectory

The trajectory of projectile, projected from the ground is given by $y = x - \frac{x^{2}}{20}$ . Where $x$ and $y$ are measured in meter. The maximum height attained by the projectile will be.

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Answer: (b)

$y = 0$ at $x = 0$ and $x = 20$ , so range $R = 20$ m; maximum at $x = 10$ m
$H = 10 - \frac{100}{20} = 5$ m
So the answer is (b) 5 m.

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