The transfer ratio β of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is 1 kΩ. The peak value of the collector AC current for an AC input voltage of 0.01 V peak is (a) 100 (b) 0.01 mA (c) 0.25 mA (d) 500

Answer: (d). Peak base current IB = (Vi)/(Ri) = (0.01)/(1000) = 10 μ A. Peak collector current IC = β IB = 50 × 10 μ A = 500 μ A. So the answer is (d) 500 μ A.

The transfer ratio β of a transistor is 50. The input resistance of… | NEET 1998 (AIPMT)

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Junction Transistor

The transfer ratio $\beta$ of a transistor is $50$ . The input resistance of the transistor when used in the common emitter configuration is $1\text{ k}\Omega$ . The peak value of the collector AC current for an AC input voltage of $0.01\text{ V}$ peak is

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Answer: (d)

Peak base current $I_B = \dfrac{V_i}{R_i} = \dfrac{0.01}{1000} = 10\ \mu$ A.
Peak collector current $I_C = \beta I_B = 50 \times 10\ \mu$ A $= 500\ \mu$ A.
So the answer is (d) $500\ \mu$ A.

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