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NEET 2012 (AIPMT, Mains) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from NEET 2012 (AIPMT, Mains)

Q68NEET 2012 · AIPMT · MAINSMedium

Transitions, Photon Emission & Excitation

The transition from the state n = 3 to n = 1 in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from

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Answer: (d)

  1. Photon energy ∝(1nf2−1ni2)\propto \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right). Infrared has much lower energy than UV, so pick the smallest bracket.
  2. 3→1:893\to1: \frac{8}{9}, 2→1:342\to1: \frac{3}{4}, 3→2:5363\to2: \frac{5}{36}, 4→2:3164\to2: \frac{3}{16}, 4→3:71444\to3: \frac{7}{144}
  3. 4→34\to3 gives the least energy (longest wavelength).
  4. So the answer is (d) 4→34 \rightarrow 3.
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