The translational degrees of freedom (ft) and rotational degrees of freedom (fr) of CH₄ molecule are: (a) ft = 2 and fr = 2 (b) ft = 3 and fr = 3 (c) ft = 3 and fr = 2 (d) ft = 2 and fr = 3

Answer: (b). CH₄ is a non-linear (tetrahedral) molecule. Translation along 3 axes: ft = 3; rotation about 3 axes: fr = 3. So the answer is (b) ft = 3, fr = 3.

The translational degrees of freedom (ft) and rotational degrees of… | JEE Main 2024 (4 Apr, Shift 2)

Q9JEE Main 2024 · 4 APR · SHIFT 2Easy

Degrees of Freedom & Internal Energy

The translational degrees of freedom $(f_t)$ and rotational degrees of freedom $(f_r)$ of $\text{CH}_4$ molecule are:

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Answer: (b)

$\text{CH}_4$ is a non-linear (tetrahedral) molecule.
Translation along 3 axes: $f_t = 3$ ; rotation about 3 axes: $f_r = 3$ .
So the answer is (b) $f_t = 3$ , $f_r = 3$ .

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