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JEE Main 2025 (29 Jan, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2025 (29 Jan, Shift 2)

Q47JEE Main 2025 · 29 JAN · SHIFT 2Medium

Logic Gates

The truth table for the circuit given below is:

Figure

Figure

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Answer: (d)

  1. Upper AND gets AA and Bˉ\bar{B}: ABˉA\bar{B}. Lower AND gets Aˉ\bar{A} and BB: AˉB\bar{A}B.
  2. Y=ABˉ+AˉBY = A\bar{B} + \bar{A}B, which is XOR.
  3. Truth table: 00→000 \to 0, 01→101 \to 1, 10→110 \to 1, 11→011 \to 0.
  4. So the answer is (d).
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