Logic Gates question from MHT CET 2026 (12 May, Shift 1)

Answer: (c)

1. First NAND: $C = \overline{AB}$.
2. Middle NANDs: $\overline{AC}$ and $\overline{BC}$.
3. Output: $Y = \overline{\overline{AC}\cdot\overline{BC}} = AC + BC = (A+B)\overline{AB} = A\bar B + \bar A B$, the XOR function.
4. Truth table: $00 \to 0,\ 01 \to 1,\ 10 \to 1,\ 11 \to 0$.
5. So the answer is (c).