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JEE Main 2026 (6 Apr, Shift 1) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2026 (6 Apr, Shift 1)

Q2JEE Main 2026 · 6 APR · SHIFT 1Medium

Young's Modulus & Elongation

The two wires $A$ and $B$ of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire $A$ and wire $B$ is 20/11. When the joined wire is kept under certain tension the elongations in the wires $A$ and $B$ are equal. If the length of wire $A$ is 2.2 m, then the length of wire $B$ is

______ m.

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Answer: (c)

Series wires carry the same tension $T$ and have equal area: $\Delta l = \frac{TL}{AY}$
Equal elongations give $\frac{L_A}{Y_A} = \frac{L_B}{Y_B}$ , so $L_B = L_A \frac{Y_B}{Y_A}$
$L_B = 2.2 \times \frac{11}{20} = 1.21\text{ m}$
So the answer is (c) 1.21.

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