The unit of permittivity of free space, ε₀, is (a) coulomb/newton-metre (b) newton-metre2/coulomb2 (c) coulomb2/newton-metre2 (d) coulomb2/(newton-metre)2

Answer: (c). Coulomb's law: F = (1)/(4πε₀)(q₁ q₂)/(r²) ⇒ ε₀ = (q₁ q₂)/(4π F r²) Unit of ε₀ = (C²)/(N m²) So the answer is (c) coulomb ² /newton-metre ².

The unit of permittivity of free space, ε₀, is | NEET 2004 (AIPMT)

Q98NEET 2004 · AIPMTEasy

Units & Dimensions

The unit of permittivity of free space, $\varepsilon_0$ , is

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Answer: (c)

Coulomb's law: $F = \frac{1}{4\pi\varepsilon_0}\frac{q_1 q_2}{r^2} \Rightarrow \varepsilon_0 = \frac{q_1 q_2}{4\pi F r^2}$
Unit of $\varepsilon_0 = \frac{\text{C}^2}{\text{N m}^2}$
So the answer is (c) coulomb $^2$ /newton-metre $^2$ .

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