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JEE Main 2017 (8 Apr, Shift 1) · P-N Junction Diode

P-N Junction Diode question from JEE Main 2017 (8 Apr, Shift 1)

Q94JEE Main 2017 · 8 APR · SHIFT 1Medium

P-N Junction Diode

The V-I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is:

Figure

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Answer: (b)

  1. Forward resistance from the linear part: Rf=ΔVΔI=0.8−0.7(20−10)×10−3=10 ΩR_f = \dfrac{\Delta V}{\Delta I} = \dfrac{0.8 - 0.7}{(20 - 10)\times 10^{-3}} = 10\ \Omega
  2. Reverse resistance: Rr=10 V1 μA=107 ΩR_r = \dfrac{10\text{ V}}{1\ \mu\text{A}} = 10^{7}\ \Omega
  3. RfRr=10107=10−6\dfrac{R_f}{R_r} = \dfrac{10}{10^{7}} = 10^{-6}
  4. So the answer is (b) 10−610^{-6}.
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