Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Series LCR Circuit›Question 13

MHT CET 2025 (5 May, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2025 (5 May, Shift 2)

Q13MHT CET 2025 · 5 MAY · SHIFT 2Easy

Series LCR Circuit

The value of alternating e.m.f. (E) in the given circuit is

Figure

Show answer and solution

Answer: (c)

  1. From the figure: VL=20V_L = 20 V, VC=50V_C = 50 V, VR=40V_R = 40 V.
  2. E=VR2+(VC−VL)2=402+302=50E = \sqrt{V_R^2 + (V_C - V_L)^2} = \sqrt{40^2 + 30^2} = 50 V
  3. So the answer is (c) 50 V.
Report a mistake

More questions on Series LCR Circuit