The value of current in the 6 Ω resistance is: (a) 4A (b) 8A (c) 10A (d) 6A

Answer: (c). Take the bottom wire at 0 and the top junction at V; both cells have + at the top. KCL: (140 - V)/(20) + (90 - V)/(5) = V/6 Multiply by 60: 420 - 3V + 1080 - 12V = 10V ⇒ V = 60 V I₆ = 60/6 = 10 A So the answer is (c) 10 A.

The value of current in the 6 Ω resistance is: | JEE Main 2021 (20 Jul, Shift 1)

Q123JEE Main 2021 · 20 JUL · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

The value of current in the 6 $\Omega$ resistance is:

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Answer: (c)

Take the bottom wire at 0 and the top junction at $V$ ; both cells have + at the top.
KCL: $\frac{140 - V}{20} + \frac{90 - V}{5} = \frac{V}{6}$
Multiply by 60: $420 - 3V + 1080 - 12V = 10V \Rightarrow V = 60\text{ V}$
$I_6 = \frac{60}{6} = 10\text{ A}$
So the answer is (c) 10 A.

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