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MHT CET 2025 (25 Apr, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2025 (25 Apr, Shift 1)

Q19MHT CET 2025 · 25 APR · SHIFT 1Easy

Kirchhoff's Laws & Measuring Instruments

The value of the shunt resistance that allows $10\%$ of the main current through the galvanometer of $99\ \Omega$ is

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Answer: (b)

Galvanometer and shunt are in parallel: $I_gG = (I - I_g)S$ .
$I_g = 0.1I \Rightarrow 0.1I \times 99 = 0.9I \times S$
$S = \dfrac{9.9}{0.9} = 11\ \Omega$
So the answer is (b) $11\ \Omega$ .

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