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JEE Main 2024 (6 Apr, Shift 1) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from JEE Main 2024 (6 Apr, Shift 1)

Q30JEE Main 2024 · 6 APR · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

The value of unknown resistance $(x)$ for which the potential difference between $B$ and $D$ will be zero in the arrangement shown, is:

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Answer: (c)

AB: $24 \parallel (12+12) = 12\ \Omega$ ; BC: $1 \parallel 1 = 0.5\ \Omega$
AD: $x + (12 \parallel 12) = x + 6$ ; DC: $0.5\ \Omega$
Balance: $\dfrac{12}{0.5} = \dfrac{x+6}{0.5} \Rightarrow x + 6 = 12$
$x = 6\ \Omega$
So the answer is (c) $6\ \Omega$ .

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