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JEE Main 2022 (26 Jun, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2022 (26 Jun, Shift 1)

Q78JEE Main 2022 · 26 JUN · SHIFT 1Easy

Acceleration Due to Gravity

The variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctly represented by:

(Given R = radius of earth)

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Answer: (a)

  1. Inside (r<Rr < R): g=GMR3r∝rg = \frac{GM}{R^3}r \propto r, straight line from 0.
  2. Outside (r>Rr > R): g=GMr2g = \frac{GM}{r^2}, decreasing curve; peak at r=Rr = R.
  3. So the answer is (a).
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