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NEET 2020 (Phase 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from NEET 2020 (Phase 2)

Q88NEET 2020 · PHASE 2Easy

Electric Potential & Equipotentials

The variation of electrostatic potential with radial distance rr from the centre of a positively charged metallic thin shell of radius RR is given by the graph

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Answer: (c)

  1. For r≤Rr \le R: E=0E = 0, so V=kQRV = \frac{kQ}{R} is constant (flat line).
  2. For r>Rr > R: V=kQrV = \frac{kQ}{r}, falling as 1r\frac{1}{r}.
  3. Graph (c) is flat up to RR and then falls as 1/r1/r, so the answer is (c).
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