Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Energy in SHM›Question 43

JEE Main 2023 (11 Apr, Shift 1) · Energy in SHM

Energy in SHM question from JEE Main 2023 (11 Apr, Shift 1)

Q43JEE Main 2023 · 11 APR · SHIFT 1Easy

Energy in SHM

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x)(x) starting from mean position to extreme position (A) is given by

Show answer and solution

Answer: (c)

  1. KE=12k(A2−x2)KE = \frac{1}{2}k(A^2 - x^2)
  2. From x=0x = 0 to x=Ax = A it falls from its maximum to zero along a downward parabola (flat at x=0x = 0, steep near AA).
  3. So the answer is (c).
Report a mistake

More questions on Energy in SHM