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MHT CET 2026 (13 Apr, Shift 1) · Scalar (Dot) Product

Scalar (Dot) Product question from MHT CET 2026 (13 Apr, Shift 1)

Q6MHT CET 2026 · 13 APR · SHIFT 1Easy

Scalar (Dot) Product

The vector sum of the two forces A⃗\vec{A} and B⃗\vec{B} is perpendicular to their vector difference. Hence forces A⃗\vec{A} and B⃗\vec{B} are

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Answer: (d)

  1. (A⃗+B⃗)⋅(A⃗−B⃗)=A2−B2=0(\vec{A} + \vec{B}) \cdot (\vec{A} - \vec{B}) = A^2 - B^2 = 0
  2. So ∣A⃗∣=∣B⃗∣|\vec{A}| = |\vec{B}|: answer (d) equal in magnitude.
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