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MHT CET 2026 (11 Apr, Shift 2) · Scalar (Dot) Product

Scalar (Dot) Product question from MHT CET 2026 (11 Apr, Shift 2)

Q7MHT CET 2026 · 11 APR · SHIFT 2Easy

Scalar (Dot) Product

The vectors $(\vec{A} + \vec{B})$ and $(\vec{A} - \vec{B})$ are perpendicular to each other. This is possible under the condition

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Answer: (a)

$(\vec{A} + \vec{B}) \cdot (\vec{A} - \vec{B}) = A^2 - B^2 = 0$
So $|\vec{A}| = |\vec{B}|$ , answer (a).

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