The velocity at which 6 kg mass (shown in figure) strikes the ground when it is released from a height of 6 m above the ground is m/s. Assume pulley is massless and string is light and inextensible. (Take g = 10 m/s²) (a) 7.74 (b) 7.20 (c) 6.55 (d) 4.50

Answer: (a). Energy conservation for the system: the 6 kg falls 6 m while the 2 kg rises 6 m; both have the same speed v. (6 - 2) × 10 × 6 = 1/2(6 + 2)v² 240 = 4v² ⇒ v² = 60 v = √(60) ≈ 7.74 m/s, option (a).

The velocity at which 6 kg mass (shown in figure) strikes the ground… | JEE Main 2026 (6 Apr, Shift 2)

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Conservation of Energy

The velocity at which 6 kg mass (shown in figure) strikes the ground when it is released from a height of 6 m above the ground is $\underline{\qquad}\ \text{m/s}$ . Assume pulley is massless and string is light and inextensible. (Take $\text{g} = 10\text{ m/s}^2$ )

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Answer: (a)

Energy conservation for the system: the 6 kg falls 6 m while the 2 kg rises 6 m; both have the same speed $v$ .
$(6 - 2) \times 10 \times 6 = \frac{1}{2}(6 + 2)v^2$
$240 = 4v^2 \Rightarrow v^2 = 60$
$v = \sqrt{60} \approx 7.74\text{ m/s}$ , option (a).

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Conservation of Energy question from JEE Main 2026 (6 Apr, Shift 2)

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