Student Login

Home›Chapters›Motion in One Dimension PYQs›Velocity, Acceleration & Variable Motion›Question 25

JEE Main 2021 (17 Mar, Shift 2) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from JEE Main 2021 (17 Mar, Shift 2)

Q25JEE Main 2021 · 17 MAR · SHIFT 2Easy

Velocity, Acceleration & Variable Motion

The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0; then its displacement after time (t = 1) is:

Show answer and solution

Answer: (b)

$x = \int_0^1 (v_0 + gt + Ft^2)\,dt$ with $x(0) = 0$
$x = \left[v_0 t + \dfrac{g t^2}{2} + \dfrac{F t^3}{3}\right]_0^1$
$x = v_0 + \dfrac{g}{2} + \dfrac{F}{3}$
So the answer is (b).

Report a mistake

More questions on Velocity, Acceleration & Variable Motion

The relation between time t and distance x for a moving body is given as t = mx2 + nx…JEE Main 2021 (25 Jul, Shift 2)
If the velocity of a body related to displacement x is given by v = √(5000 + 24x) m/s…JEE Main 2021 (27 Aug, Shift 1)
The distance x covered by a particle in one dimensional motion varies with time t as x2 =…JEE Main 2020 (9 Jan, Shift 1)
The position of a particle as a function of time t, is given by x(t) = at + bt2 – ct3…JEE Main 2019 (9 Apr, Shift 2)
The position vector of a particle changes with time according to the relation r(t) =…JEE Main 2019 (9 Apr, Shift 2)
A particle is moving with speed v = b √(x) along positive x-axis. Calculate the speed of…JEE Main 2019 (12 Apr, Shift 2)
Two cars P and Q start from a point at the same time in a straight line and their…NEET 2016 (Phase 2)
If the velocity of a particle is v = At + Bt2, where A and B are constants, then the…NEET 2016 (Phase 1)