Physics Circle home Student Login

Home›Chapters›Projectile Motion PYQs›Velocity, Momentum & Energy in Flight›Question 15

NEET 2013 · Velocity, Momentum & Energy in Flight

Velocity, Momentum & Energy in Flight question from NEET 2013

Q15NEET 2013Easy

Velocity, Momentum & Energy in Flight

The velocity of a projectile at the initial point A is (2i^+3j^)\left(2\hat{i} + 3\hat{j}\right) m/s. Its velocity (in m/s) at point B is

Figure

Show answer and solution

Answer: (a)

  1. Horizontal velocity stays 2i^2\hat i throughout.
  2. B is at the same level as A, so the vertical velocity has the same size but is reversed: −3j^-3\hat j
  3. So the answer is (a) 2i^−3j^2\hat i - 3\hat j.
Report a mistake

More questions on Velocity, Momentum & Energy in Flight