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JEE Main 2022 (28 Jun, Shift 1) · Beats

Beats question from JEE Main 2022 (28 Jun, Shift 1)

Q45JEE Main 2022 · 28 JUN · SHIFT 1Medium

Beats

The velocity of sound in a gas, in which two wavelengths 4.08 m and 4.16 m produce 40 beats in 12s, will be:

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Answer: (d)

  1. Beat frequency =4012=103 Hz= \dfrac{40}{12} = \dfrac{10}{3}\text{ Hz}.
  2. v(14.08−14.16)=103⇒v⋅0.084.08×4.16=103v\left(\dfrac{1}{4.08} - \dfrac{1}{4.16}\right) = \dfrac{10}{3} \Rightarrow v \cdot \dfrac{0.08}{4.08 \times 4.16} = \dfrac{10}{3}
  3. v=10×16.973×0.08≈707.2 m/sv = \dfrac{10 \times 16.97}{3 \times 0.08} \approx 707.2\text{ m/s}
  4. So the answer is (d) 707.2 m s−1707.2\text{ m s}^{-1}.
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