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JEE Main 2022 (27 Jul, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2022 (27 Jul, Shift 2)

Q22JEE Main 2022 · 27 JUL · SHIFT 2Medium

Equations of Kinematics

The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4 + x) cm inside the block. The value of x is:

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Answer: (c)

Constant resistance means constant retardation, so the drop in $v^2$ is proportional to distance.
First 4 cm: $u^2 - \frac{u^2}{9} = \frac{8u^2}{9} = 2a(4)$
Further $x$ : $\frac{u^2}{9} = 2a(x)$
$\frac{x}{4} = \frac{1}{8} \Rightarrow x = 0.5\text{ cm}$
So the answer is (c) 0.5.

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