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MHT CET 2025 (21 Apr, Shift 1) · Graphs of Motion

Graphs of Motion question from MHT CET 2025 (21 Apr, Shift 1)

Q4MHT CET 2025 · 21 APR · SHIFT 1Easy

Graphs of Motion

The velocity time graph of a body moving in a straight line is shown in figure. The ratio of displacement to distance travelled by the body in time 0 to 8 s is

Figure

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Answer: (c)

  1. Read the graph (not to scale) as: +3+3 m/s for 00-22 s, −2-2 m/s for 22-33 s, +2+2 m/s for 33-55 s, −2-2 m/s for 55-66 s, +2+2 m/s for 66-88 s.
  2. Positive area =6+4+4=14 m= 6 + 4 + 4 = 14\text{ m}; negative area =2+2=4 m= 2 + 2 = 4\text{ m}
  3. Displacement =14−4=10 m= 14 - 4 = 10\text{ m}; distance =14+4=18 m= 14 + 4 = 18\text{ m}
  4. Ratio =10:18=5:9= 10 : 18 = 5 : 9, so the answer is (c).
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