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MHT CET 2026 (13 Apr, Shift 2) · Graphs of Motion

Graphs of Motion question from MHT CET 2026 (13 Apr, Shift 2)

Q1MHT CET 2026 · 13 APR · SHIFT 2Easy

Graphs of Motion

The velocity time graph of a body moving in a straight line is shown in a figure. The ratio of displacement to distance travelled by the body in time 00 to 1010 s is

Figure

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Answer: (d)

  1. Areas: 00-22 s: 8×2=168 \times 2 = 16; 22-44 s: −4×2=−8-4 \times 2 = -8; 44-88 s: 4×4=164 \times 4 = 16; 88-1010 s: −4×2=−8-4 \times 2 = -8 (m)
  2. Displacement =16−8+16−8=16 m= 16 - 8 + 16 - 8 = 16\text{ m}
  3. Distance =16+8+16+8=48 m= 16 + 8 + 16 + 8 = 48\text{ m}
  4. Ratio =16:48=1:3= 16 : 48 = 1 : 3, so the answer is (d).
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