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JEE Main 2025 (28 Jan, Shift 2) · Graphs of Motion

Graphs of Motion question from JEE Main 2025 (28 Jan, Shift 2)

Q5JEE Main 2025 · 28 JAN · SHIFT 2Easy

Graphs of Motion

The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between $t = 0$ to $t = 4\text{ s}$ ?

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Answer: (b)

Distance = area under the $v$ - $t$ graph from 0 to 4 s.
0 to 2 s (triangle): $\frac{1}{2}\times 2\times 10 = 10\text{ m}$
2 to 4 s (rectangle): $2\times 10 = 20\text{ m}$
Total $= 30\text{ m}$ . So the answer is (b).

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