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NEET 2006 (AIPMT) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from NEET 2006 (AIPMT)

Q79NEET 2006 · AIPMTEasy

Applications of Dimensional Analysis

The velocity v of a particle at time t is given by v = at + bt+c\frac{b}{t + c}, where a, b and c are constants. The dimensions of a, b and c are

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Answer: (b)

  1. atat has dimensions of velocity: [a]=[LT−1]/[T]=[LT−2][a] = [LT^{-1}]/[T] = [LT^{-2}].
  2. cc is added to tt: [c]=[T][c] = [T].
  3. b/(t+c)b/(t+c) is a velocity: [b]=[LT−1][T]=[L][b] = [LT^{-1}][T] = [L].
  4. So the answer is (b) [LT−2],[L],[T][LT^{-2}], [L], [T].
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