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JEE Main 2022 (29 Jun, Shift 2) · Least Count, Vernier Callipers & Screw Gauge

Least Count, Vernier Callipers & Screw Gauge question from JEE Main 2022 (29 Jun, Shift 2)

Q32JEE Main 2022 · 29 JUN · SHIFT 2Medium

Least Count, Vernier Callipers & Screw Gauge

The Vernier constant of Vernier callipers is 0.1 mm and it has zero error of ( $-$ 0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be _________ $\times$ 10 $-$ 2 cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 180

VC $= 0.1$ mm $= 0.01$ cm
Observed $= 1.7 + 5\times 0.01 = 1.75$ cm
Corrected $= 1.75 - (-0.05) = 1.80$ cm $= 180\times10^{-2}$ cm
Answer: 180

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