The vertical component of the earth's magnetic field is 6 × 10⁻⁵ T at any place where the angle of dip is 37°. The earth's resultant magnetic field at that place will be ( Given tan 37° = 3/4) (a) 8 × 10⁻⁵ T (b) 6 × 10⁻⁵ T (c) 5 × 10⁻⁴ T (d) 1 × 10⁻⁴ T

Answer: (d). V = BEsin δ; tan 37° = 3/4 ⇒ sin 37° = 3/5 BE = (V)/(sin 37°) = 6 × 10⁻⁵0.6 = 1 × 10⁻⁴ T So the answer is (d) 1 × 10⁻⁴ T.

The vertical component of the earth's magnetic field is 6 × 10⁻⁵ T at… | JEE Main 2022 (29 Jul, Shift 2)

Q1JEE Main 2022 · 29 JUL · SHIFT 2Easy

Earth's Magnetism

The vertical component of the earth's magnetic field is $6 \times 10^{-5}\text{ T}$ at any place where the angle of dip is $37^\circ$ . The earth's resultant magnetic field at that place will be $($ Given $\tan 37^\circ = \frac{3}{4})$

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Answer: (d)

$V = B_E\sin\delta$ ; $\tan 37^\circ = \frac{3}{4} \Rightarrow \sin 37^\circ = \frac{3}{5}$
$B_E = \frac{V}{\sin 37^\circ} = \frac{6 \times 10^{-5}}{0.6} = 1 \times 10^{-4}\ \text{T}$
So the answer is (d) $1 \times 10^{-4}\ \text{T}$ .

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