The voltage between the plates of a parallel plate capacitor of capacity 1 is changing at the rate of 4 V/s. the displacement current in the capacitor is (a) 4 (b) 3 (c) 1 (d) 6

Answer: (a). Displacement current Id = CdV/dt. Id = (1×10⁻⁶)(4) = 4×10⁻⁶ A So the answer is (a) 4.

The voltage between the plates of a parallel plate capacitor of… | MHT CET 2025 (21 Apr, Shift 1)

Q4MHT CET 2025 · 21 APR · SHIFT 1Easy

Capacitors in DC Circuits & RC

The voltage between the plates of a parallel plate capacitor of capacity $1\ \mu\text{F}$ is changing at the rate of $4\text{ V/s}$ . the displacement current in the capacitor is

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Answer: (a)

Displacement current $I_d = C\dfrac{dV}{dt}$ .
$I_d = (1\times10^{-6})(4) = 4\times10^{-6}\text{ A}$
So the answer is (a) $4\ \mu\text{A}$ .

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