Physics Circle home Student Login

Home›Chapters›Semiconductor Electronics PYQs›Junction Transistor›Question 112

NEET 2008 (AIPMT) · Junction Transistor

Junction Transistor question from NEET 2008 (AIPMT)

Q112NEET 2008 · AIPMTMedium

Junction Transistor

The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be

Show answer and solution

Answer: (b)

  1. With negative feedback: Af=A1+βAA_f = \dfrac{A}{1 + \beta A}, β=0.09\beta = 0.09, Af=10A_f = 10
  2. 10(1+0.09A)=A⇒10+0.9A=A10(1 + 0.09A) = A \Rightarrow 10 + 0.9A = A
  3. 0.1A=10⇒A=1000.1A = 10 \Rightarrow A = 100
  4. So the answer is (b) 100.
Report a mistake

More questions on Junction Transistor