The voltmeter has range 10 V and its internal resistance is 50 Ω. To increase the range of voltmeter to 15 V, the resistance which is to be connected is (a) 125 Ω resistance in parallel (b) 125 Ω resistance in series (c) 25 Ω resistance in parallel (d) 25 Ω resistance in series

Answer: (d). To raise a voltmeter's range a resistance is added in series: R = G(V'/V - 1). R = 50(15/10 - 1) = 50 × 0.5 = 25 Ω So the answer is (d) 25 Ω resistance in series.

The voltmeter has range 10 V and its internal resistance is 50 Ω. To… | MHT CET 2025 (22 Apr, Shift 1)

Q20MHT CET 2025 · 22 APR · SHIFT 1Easy

Kirchhoff's Laws & Measuring Instruments

The voltmeter has range 10 V and its internal resistance is $50\ \Omega$ . To increase the range of voltmeter to 15 V, the resistance which is to be connected is

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Answer: (d)

To raise a voltmeter's range a resistance is added in series: $R = G\left(\frac{V'}{V} - 1\right)$ .
$R = 50\left(\frac{15}{10} - 1\right) = 50 \times 0.5 = 25\ \Omega$
So the answer is (d) $25\ \Omega$ resistance in series.

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