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JEE Main 2024 (9 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2024 (9 Apr, Shift 1)

Q118JEE Main 2024 · 9 APR · SHIFT 1Medium

Thermodynamic Processes

The volume of an ideal gas (γ=1.5)(\gamma = 1.5) is changed adiabatically from 5 litres to 4 litres. The ratio of initial pressure to final pressure is:

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Answer: (b)

  1. Adiabatic: P1V1γ=P2V2γ⇒P1P2=(V2V1)γP_1V_1^\gamma = P_2V_2^\gamma \Rightarrow \frac{P_1}{P_2} = \left(\frac{V_2}{V_1}\right)^\gamma.
  2. P1P2=(45)3/2=855\frac{P_1}{P_2} = \left(\frac{4}{5}\right)^{3/2} = \frac{8}{5\sqrt{5}}
  3. So the answer is (b) 855\frac{8}{5\sqrt{5}}.
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